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In the following code, what will be printed when run in Miracle C? Why? (Code needed to make this a complete program intentionally left out

Computer Science Sep 02, 2020

In the following code, what will be printed when run in Miracle C? Why? (Code needed to make this a complete program intentionally left out.)

int j;
while (j < 3)
{
printf("The value of j = %d",j);
j = j + 1;
}
printf("Done! ";);

Expert Solution

Here is a corrected code (also attached):

int j;
j = 0 ;

while (j < 3)
{
printf("The value of j = %dn",j);
j = j + 1;
}
printf("Done!n");

Here is output:

The value of j = 0
The value of j = 1
The value of j = 2
Done!

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