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52

Math

52. How can a graph be used to determine how many solutions an equation has?

  I know that it deals with how many times the graph crosses the x-axis.

??????

 

Section 6.8

8.

Bobbi is working at 1 qt / 20 min.

Blanche is working at 1 qt / 25 min.

 

Let’s add their speeds together:

 

1/20 + 1/25 = 9/100 qt / min

 

At that speed, how long would it take them to pick one quart?

 

9/100 qt     =  9 qt / 100 min   =          1 qt 

min                                                      100/9 min

 

It will take them 100/9 minutes (11.111 minutes) if they worked together.

 

I  must provide an algebraic equation with my solution. Algebraic equations have variables which are defined. 

14.  The speed of a freight train is 15 mph slower than the speed of a passenger train. 

      The freight train travels 390 mi  in the same time that it takes the passenger train to

       travel  480 mi.  Find the speed of each train.

 

 

 

F = speed of the freight train, and P = speed of the passenger train:

 

            F = P – 15

 

            390/F = 480/P

 

Combine the equations and solve for P:

 

            (P – 15)           =          P

            390                              480

 

            480(P – 15)     =          390(P)

           

            480P – 7200    =          390P

 

            90P -7200 = 0

 

            90P = 7200

 

            P = 80

 

Since, F = P – 15, then F = 65

 

     Im suppose to clearly state the answer with units                                                        

                                                                           2

44.  It takes 60 oz. of grass seed to seed 3000 ft   of lawn.  At this rate, how much would

       be needed to seed             2       of  lawn?

                                     5000 ft

60 oz   =          x

3000                5000

 

Cross-multiply and solve for x:

 

60(5000) = 3000x

 

x = 100

I  must define the  answer and i must provide units with the answer

 

 

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52. How can a graph be used to determine how many solutions an equation has?

Plot y against x. The values of x at which the plot cuts the x axis are the solutions. The number of points at which the x axis is crossed is the number of solutions.

8. Bobbi picks 1 qt in 20 minutes. Blanche picks 1 qt in 25 minutes. How long would it take them to pick one quart if they work together?

Let the rate at which Bobbi works = x qt/min
Let the rate at which Blanche works = y qt/min
Combined rate = x + y qt/min
Time taken to pick 1 qt = 1 qt / (x+y) qt/min = 1/ (1/20+ 1/25) = 1/ {(5+4)/ 100}
= 100/9 minutes = 11 1/9 minutes

14. The speed of a freight train is 15 mph slower than the speed of a passenger train. The freight train travels 390 miles in the same time that it takes the passenger train to travel 480 miles. Find the speed of each train.

F = speed of the freight train in miles/hr, and P = speed of the passenger train in miles/hr:
F = P - 15 miles/ hr
Time taken to cover 390 miles for freight train = 390 miles / F miles/hr = 390 /F hr
Time taken to cover 480 miles for passenger train = 480 miles / P miles/hr = 480 /P hr
According to the conditions in the problem
390/F hr = 480/P hr
Combining the equations and solving for P:

(P - 15) = P
390 480

480(P - 15) = 390(P)

480P - 7200 = 390P

90P -7200 = 0

90P = 7200

P = 80

Since, F = P - 15, then F = 65

Therefore, speed of Freight train = F miles/hr = 65 miles/hr
Speed of Passenger train = P miles/hr = 80 miles/hr

44. It takes 60 oz. of grass seed to seed 3000 ft ^2 of lawn. At this rate, how much would be needed to seed 5000 ft^2 of lawn?

Amount of grass seed required to seed 3000 ft 2 of lawn = 60 oz
Therefore, amount of grass seed required to seed 1 ft 2 of lawn
= 60 oz ( 1 ft 2 / 3000 ft 2 ) = 60 / 3000 oz = (1/ 50) oz
Amount of grass seed required to seed 5000 ft 2 of lawn = 5000 (1/50) oz = 100 oz

Alternatively;
Let x oz be the amount required to seed 5000 ft 2 of lawn

60 oz = x oz
3000 ft 2 5000 ft 2
Cross-multiplying and solving for x:

60(5000) = 3000x

Or x = 100
Therefore, amount of seed required = x oz = 100 oz