Fill This Form To Receive Instant Help
Homework answers / question archive / Foothill College ANTH 001 Module: 4 1)In a hypothetical situation, B is the allele that causes brachydactyly
Foothill College
ANTH 001
Module: 4
1)In a hypothetical situation, B is the allele that causes brachydactyly. If a man who has normal fingers (bb) and a woman with brachydactyly (Bb) have children, what proportion of these children would you expect to have
normal fingers? (Hint: Use a Punnett square).
genetic locus?
an enzyme.
different traits.
production?
11. A woman has the genotype XCXc and a man has the genotype XcY. They
have a 25% chance of having a female child who is colorblind.
12. A woman with normal skin pigmentation has five children with an albino man. Four of the children have normal pigmentation and one child is an
albino. The woman's genotype must be Aa.
different traits.
taste PTC?
genotype?
pressures, and allele frequencies.
20. A woman with normal skin pigmentation has five children with an albino
man. Four of the children have normal pigmentation and one child is an albino. The woman's genotype must be Aa.
21. Recessive conditions are usually associated with the lack of production of
an enzyme.
22. A man who has type A blood has the AA genotype. His wife, with type B blood, has the BO genotype. Which of the following blood types is/are
NOT possible for their children?
in homozygotes, it is said to be:
27. A woman has the genotype XCXc and a man has the genotype XcY. They have a 50% chance of having a male child who has normal color vision.
pressures, and allele frequencies.