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Homework answers / question archive / if f(x) = e2xy then find fx, fy, fxx, fxy, fyx, fyy
if f(x) = e2xy then find fx, fy, fxx, fxy, fyx, fyy .
Given function is f( x ) = e2xy
we have to calculate fx, fy, fxx, fxy, fyx, fyy
these are first order and second order derivative with respects to x , y.
fx = ∂f / ∂x
= ∂( e2xy ) / ∂x ( differntaition of eax = a eax and if a is a function of x its differentaition with respect to x should be done.)
= e2xy * 2y
fy = ∂f / ∂y
= ∂( e2xy ) / ∂y
= e2xy * 2x
fxx = ∂2f / ∂2x
double differentiation of function with respect to x.
we know that fx = e2xy * 2y
so fxx = 2y * e2xy * 2y
fxx = 4y2 e2xy
fyy = ∂2f / ∂2y
double differentiation of function with respect to y.
we know that fy = e2xy * 2x
so fyy = 2x * e2xy * 2x
fyy = 4x2 e2xy
fxy = ∂2f / ∂x ∂y
differentaition of of fx with respect to y.
we know that fx = e2xy * 2y
so fxy = using product rule
e2xy 2 + 2y *e2xy * (2x)
2e2xy ( 1 + 2xy )
fyx = ∂2f / ∂y ∂x
differentiation of fy with respect to x
we know that fy = e2xy * 2x ( using product rule)
so fyx = e2xy (2) + 2x *e2xy * (2y)
fyx = 2e2xy ( 1 + 2xy )