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A 21

Chemistry

A 21.5 g sample of a metal is immersed in boiling water at 100.0º C and then transferred to a calorimeter containing 75.0 g of water at 22.5ºC . The final temperature of the water is 27.0ºC. What is the specific heat of the metal? 

 

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Using the concept of specific heat capacities, 

heat released = heat absorbed

q = m * s * ?T

here m = mass

s = specific heat capacity

s of water = 4.2 j / g °c

?T = change in temperature

qmetal = qwater

 

21.5 * s * ( 100 - 27) °c = 75 * 4.2 * ( 27 - 22.5 ) °c

 

s = (315 * 4.5 )/ (21.5 * 73)

s = 1417.5 / 1569.5

s = 0.90 j / (g °c)