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Part C What is produced at each electrode in the electrolysis of an aqueous solution of both NaBr and AgF?

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Anode Cathode not produced

Na(s) H2(g) Ag(s) F2(g) O2(g) Br2(l)

pur-new-sol

reduction potential of Ag+/Ag = 0.80V

the oxidation potential of Br-/Br2 = -1.066V

reduction potential of Na+/Na = 2.71V

reduction potential of 2H+/H2 = 0.00V

oxidation potential of 2F-/F2 = -2.87V

oxidation potential of 2H2O-----> O2 + 4H+ + 4e= -1.23V

at cathode reduction will occur so here Ag(s) will form becaue its reduction potential is high

and at anode oxidation will occur and , here the substance with high oxidation potential can oxidise easily so bromine will form.

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