A monoprotic acid, HA, is dissolved in water: The equilibrium concentrations of the reactants and products are [HA] = 0

Chemistry Jan 09, 2021

A monoprotic acid, HA, is dissolved in water: The equilibrium concentrations of the reactants and products are [HA] = 0.160 M [H ] = 4.00

Expert Solution

A monoprotic acid dissociates according to the reaction equation:
HA(aq) ------> H+(aq) + A-(aq)

The equilibrium concentrations in M satisfy the relation:
Ka = [H+]·[A-] / [HA]

For this acid
Ka = (4.00×10^-4 * 4.00×10^-4 )/ 0.16 M
Ka= 10^-6

Hence,
pKa = - log10(Ka) = - log10(10^-6) = 6

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