2NO−3(aq)+8H+(aq)+3Cu(s)→2NO(g)+4H2O(l)+3Cu2+(aq) Part A Indicate the half-reaction occurring at Anode

Chemistry Jan 14, 2021

2NO−3(aq)+8H+(aq)+3Cu(s)→2NO(g)+4H2O(l)+3Cu2+(aq)

Part A Indicate the half-reaction occurring at Anode. Express your answer as a chemical equation. Identify all of the phases in your answer.

Part B Indicate the half-reaction occurring at Cathode. Express your answer as a chemical equation. Identify all of the phases in your answer.

Expert Solution

Oxidation occurs at anode
Cu is oxidised to Cu(II) ions.
The half reaction ocuring at anode is
$Cu(s) \rightarrow Cu^{2+}(aq) + 2e^-$
Reduction occurs at cathode
Nitrate ion is reduced to nitric oxide.
The half reaction ocuring at cathode is
$2NO_3^- (aq) + 8H^+(aq) +6e^- \rightarrow 2NO(g) + 4H_2O(l)$
Note: 2 electrons are involved in the oxidation half reaction. In the overall reaction, the oxidation half reaction is multiplied by 3 to balance Cu atoms. Hence, in the reduction half reaction, total six electrons participate.
The reduction half reaction can also be written as
$NO_3^- (aq) + 4H^+(aq) +3e^- \rightarrow NO(g) + 2H_2O(l)$
Here the coefficent of each spcies is divided by 2.

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