Fill This Form To Receive Instant Help

Help in Homework
trustpilot ratings
google ratings


Homework answers / question archive / Suppose the (external) damage done by pollution is known to be MD=300+5q, and the (private) cost and benefit are given by MC=100+2q and MB=D-2q, where D is not known

Suppose the (external) damage done by pollution is known to be MD=300+5q, and the (private) cost and benefit are given by MC=100+2q and MB=D-2q, where D is not known

Marketing

Suppose the (external) damage done by pollution is known to be

MD=300+5q, and the (private) cost and benefit are given by

MC=100+2q and MB=D-2q, where D is not known.

a)If d=1000, what would be the optimal quantity? What tax would be necessary in order for that to be the equilibrium quantity?

b)Suppose that, based on the result from part (a), a cap-and-trade system is imposed to allow the optimal quantity of pollution to be produced. If D=900, what would be the dead-weight loss associated with having the wrong quantity?

c)Suppose that, based on the result from part (a), a tax is imposed to allow the optimal quantity of pollution to be produced. If D=900, what would be the dead-weight loss associated with the wrong tax level?

d)If D is not exactly known, which is likely to give better results, a cap-and-trade system or a tax? What would be the answer to this question if MD were 300+3Q instead of 300+5q

pur-new-sol

Purchase A New Answer

Custom new solution created by our subject matter experts

GET A QUOTE

Answer Preview

A.

At D=1000, equilibrium quantity and Marginal Private Benefit (MPB) would be:

MB=MC100+2q=D−2q100+2q=1000−2q4q=900q=225MB=100+2(225)=550MB=MC100+2q=D−2q100+2q=1000−2q4q=900q=225MB=100+2(225)=550

Optimum quantity is:

MD=MB300+5q=D−2q300+5q=1000−2q7q=700q=100MD=300+5(100)=800MD=MB300+5q=D−2q300+5q=1000−2q7q=700q=100MD=300+5(100)=800

To bring q to the equilibrium quantity to 225 from 100, tax equivalent to external damage (MD) or external cost is needed. That is MD-MC

=MD−MC=800−550=250=MD−MC=800−550=250

B.

If D=900, optimal quantity is:

MD=MB300+5q1=D−2q1300+5q1=900−2q17q=600q1=85.71MD1=300+5(85.71)=728.55MD=MB300+5q1=D−2q1300+5q1=900−2q17q=600q1=85.71MD1=300+5(85.71)=728.55

Deadweight loss associated would be:

=0.5(MD−MD1)(q−q1)=0.5(800−728.55)(1000−900)=3572.5=0.5(MD−MD1)(q−q1)=0.5(800−728.55)(1000−900)=3572.5

C.

With D=900 the correct amount of tax imposed should be:

=MD−MC=728.55−550=178.55=MD−MC=728.55−550=178.55

and tax imposed=250, the extra amount of tax would be:

=250−178.55=71.45DWL=0.5(71.45)(1000−900)=3572.5=250−178.55=71.45DWL=0.5(71.45)(1000−900)=3572.5

Where DWL is deadweight loss.

D.

Considering D is not known, cap and trade system is better one. The deadweight loss would be minimum because the sellers can trade whatever marginal damage they created. Tax is ideal only for scenario when exact D is known, otherwise there would be deadweight loss.

If MD=300+3q, optimal quantity is:

MD=MB300+3q=D−2q300+3q=1000−2q5q=700q=140MD=300+3(140)=720MD=MB300+3q=D−2q300+3q=1000−2q5q=700q=140MD=300+3(140)=720

Tax would be:

=720−550=170=720−550=170

As here, marginal damage is less, tax can be imposed. Deadweight loss would be less.

Related Questions