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VIRTUAL EXPERIMENT 2. Mystery Bottles
Watch ALL the associated videos and then complete the quiz. You won’t get access to the quiz until all content is viewed. No extensions granted on the quiz.
Use the solubility rules in your lab assignment to make predictions. This quiz is meant to be done WITH your lab manual. In other words, it’s open book to encourage you to read all parts of the Mystery Bottles experiment. Hint: Fill in the mixing prediction table before starting the quiz.
The objective of this experiment is to use your knowledge about acid-base and precipitation reactions that occur in aqueous solutions to identify the ionic substances present in a set of solutions. Flame tests will also be used to identify the content of the 7 mystery bottles.
Course Objectives
The unknown solutions will be labeled A through G and you will be given the list of cations and anions that are present. All the solutions that you will be given are clear; hence you can already conclude that only cation/anion combinations that do not react with each other have been selected. Recall that when a cation and anion are mixed, a reaction occurs only if a precipitate is observed or a covalent compound (such as water or a gas) is formed. In order to help you determine the unknowns, a set of solubility rules is required. There are many versions of the rules but the following can be helpful since they are listed in hierarchical order. For example, rule 1 takes precedence over rule 2 and so on.
Thus, for example, using these rules we can predict that NaOH is soluble (Rule 1 takes precedence over Rule 7), that Pb(C2H3O2)2 is soluble (Rule 2 takes precedence over Rule 3) and that AgBr is insoluble (Rule 5 takes precedence over Rule 6).
As a simple illustration of the purpose of this experiment, suppose you are given three clear solutions X, Y and Z and are told that the solutions may contain the cations Na+, H3O+ and Ag+ (each ion used once) and the anions CO32−, ClO3− and Br−. Since the solutions are clear, you may conclude that one solution does not contain AgBr since AgBr is insoluble in water and would form a precipitate (Rule 5 takes precedence over Rule 6). Likewise, one solution does not contain Ag2CO3 since this compound is also insoluble (Rule 5 takes precedence over Rule 7). Thus, one solution must be AgClO3. In a similar fashion, you know that none of the unknowns can contain both H3O+ and CO32-, because hydronium ion and carbonate ion react to form carbon dioxide gas and water according to the following equation 1:
CO32− (aq) + 2 H3O+(aq) → H2CO3(aq) → CO2(g) + H2O(l) (1)
Thus, the others must be (H3O)Br and Na2CO3. You could identify which is which by systematically mixing pairs of solutions and observing what happens. Suppose you mix X with Y and observe the formation of a pale yellow precipitate. Since Na+ and H3O+ compounds are soluble, either X or Y must contain AgNO3, and the reaction which occurs must be one of the following 2 or 3:
2 Ag+(aq) + CO32- (aq) → Ag2CO3(s) (2)
Ag+(aq) + Br−(aq) → AgBr(s) (3)
Suppose you now mix X with Z and also observe a yellow precipitate. Then, one of the above two reactions must have occurred; this identifies X as AgClO3(aq). The identity of Y and Z is still unclear. If you mix Y and Z, you will observe bubbles due the reaction described in (1). We have no evidence at this point about Na+ and H3O+.
A flame test could be used to differentiate between these ions. In a flame test, when atoms of a metal are given extra energy (in this case placed into a flame), its electrons are promoted to higher energy levels. When the electrons return to their original energy level, the excess energy is given off as photons. The wavelengths given off are characteristic of the metal, just like the wavelengths produced by a gas discharge tube are characteristic of the specific element inside it.
Na gives a bright orange-yellow flame test, while H3O+ gives no discernable color in a flame. So, if Z burns orange-yellow, then it must be Na2CO3. In addition, testing the unknown solutions with litmus paper can aid in our identification of the unknowns, as the presence of H3O+ will cause blue litmus to turn red. So, if Y produces a red litmus test, it must be H3OBr.
In your experiment, the unknown bottles are labeled I - VII. These unknowns contain the following cations and anions: Ag+, Ba2+, Co2+, H3O+, Li+, Na+, Sr2+ and Cl−, CO32−, OH−, NO3−, SO42−. Each solution contains a different cation, but more than one solution can contain the same anion. Recall that a salt solution must contain both a cation and an anion.
Part A. Solution Set- up
1. Obtain about 8 mL of each solution in separate medium test tubes. Label the test tubes carefully. If you pour out more solution than this, do not return any of it to the reagent bottle; just discard what is left over into the inorganic waste container at the end of your work. Place a clean glass Pasteur pipet in each test tube.
Part B. Litmus Tests
1. Test the acidity or basicity of each solution by dipping a clean glass stirring rod into the solution and placing a drop of the solution onto strips of neutral litmus paper.
An acidic solution (H3O+ present) will turn litmus paper red and a basic solution (OH− or CO32− present) will turn litmus paper blue.
Part C. Mixing Solutions
Observe any evidence of a reaction occurring, such as formation of a precipitate or evolution of a gas (bubbles). Record your observations.
Part D. Flame Tests
The colors of flames are: Li – carmine red; Ba – green; Na – orange-yellow; Sr – crimson red. The other ions give no characteristic flame test color.
Every solution that has been stored in a glass vessel will give a positive Na test due to the leaching of sodium from the glass. Thus, a positive flame test due to a dissolved unknown Na salt should exhibit a persistent and very intense orange-yellow color.
As a corollary, the colors due to other cations are visible briefly after the yellow of the leachedin Na disappears. Because you have other criteria besides flame tests for determining the ions present, no “known” solutions will be provided for comparison.
Make some tentative hypotheses about which solution contains which cations based on the above results. Since each of the possible cations is present in one of the unknown solutions, you should observe a single occurrence of each of the flame colors described above. Consider testing each solution more than once to confirm your hypothesis.
Clean up: Glass Pipettes go in glass disposal containers only (white and blue box in the lab). Pipette bulbs are returned to original location. Dispose of all solutions in appropriate waste containers. Clean test tubes and return to bin.
There is no quantitative data for this experiment. All of the qualitative data can be observed from the lab video (once released) and used for the fillable lab report.
A fillable lab report must be downloaded from MyLS and used to write this lab report. You cannot alter the order of the tables given in the document and marks will be deducted if you do not use the fillable document.
You may add your own clearly labelled tables to the discussion only.
No abstract is required for this lab report. There is some information and ideas below to assist with your lab report.
Fill in this mixing prediction table detailing what you predict will happen when these ions are mixed. This can be done using the solubility rules given in the theory. (NR = no reaction)
*Mixing Prediction table |
Cl- |
CO32- |
OH- |
NO3- |
SO42- |
Ag+ |
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Ba2+ |
NR |
BaCO3 |
Ba(OH)2 |
NR |
BaSO4 |
H3O+ |
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Li+ |
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Na+ |
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NR |
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Co2+ |
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Sr2+ |
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EXAMPLE of how to fill in this OPTIONAL table labelled #7 in your fillable document. If you need a starting point, this could be useful but is not required.
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You have narrowed down that the unknown X should be Lithium which could have the nitrate, chlorite or sulfate ions paired with it. You think the unknown Y is Calcium which could be paired with acetate or chlorate. If X and Y react together, the negative ions of Y would be paired with Lithium and the negative ions of X would be paired with Calcium (double displacement (like a criss/cross) reaction).
IF the reaction between X and Y resulted in a precipitate, then Lithium must contain the sulfate ion in order for Calcium Sulfate to be formed as it’s the only precipitate possible out of all of the combinations. (Conversely, if a precipitate wasn’t formed, then sulfate could NOT be one of ions with Lithium).
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