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Balance the following redox reaction by inserting the appropriate coefficients
Balance the following redox reaction by inserting the appropriate coefficients.
HNO3 + H2S ----> NO +S + H2O
Expert Solution
1). In H 2 S + HNO 3 -> NO +S + H 2 O
At first we will, consider for both the half reactions
H 2 S (aq) -> 2H + (aq.) + S (s) + 2e - -->eq.1.
Similarly, HNO 3(aq) + 3H + (aq) + 3e - -> 2NO (g) + 2H 2 O (l) ---eq.2
Now, to balance no. of electrons in both the side we multiply eq.1 with 3 and eq. 2with 2and then add them to get the resultant balanced reaction as:
[H 2 S (aq) -> 2H + (aq.) + S (s) + 2e - ] x 3
[HNO 3(aq) + 3H + (aq) + 3e - -> NO (g) + 2H 2 O (l) ] x2
3 H 2 S (aq) + 2 HNO 3(aq) -> 2NO (g) + 4H 2 O (l) + 3S
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