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A loan is amortized over 8 years with monthly payments at a nominal interest rate of 9% compounded monthly
A loan is amortized over 8 years with monthly payments at a nominal interest rate of 9% compounded monthly. The first payment is $1200 and is to be paid one month from the date of the loan. Each succeeding monthly payment will be 2% lower than the prior payment. Calculate the outstanding loan balance immediately after the 79th payment is made. ANSWER = $
Expert Solution
| First, we will find the Present value, PV of the loan |
| Using the formula for PV of growing annuity & assigning -ve sign, for the growth , to denote decrease |
| PV(g)A=Pmt./(r-g)*(1-((1+g)/(1+r))^n) |
| where, |
| PV(g)A----- needs to be found out---?? |
| Pmt.=the first end-of-month payments, ie. $ 1200 |
| r= 9%/12= 0.75% or 0.0075 p.m |
| g= negative growth rate , ie. -2% or -0.02 p.m. |
| n= no.of compounding mths., ie. 8 yrs.*12= 96 |
| Now, we will plug in the values , in the formula, |
| PV=(1200/(0.0075-(-0.02)))*(1-((1-0.02)/(1+0.0075))^96) |
| 40574.21 |
| So, PV of the loan= $ 40574.21 |
| Now, the balance o/s on the loan after the 79 th payment is |
| FV of the single sum of $ 40574.21 at end of 79 th mthly .pmt.-FV of 79-mths , ordinary mth.end 2% decreasing annuity of $ 1200 |
| ie. FV of single sum-FV of negatively growing mthly.annuity |
| Balance o/s at end mth.79=(PV*(1+r)^n)-(Pmt.*(((1+r)^n-(1+g)^n)/(r-g))) |
| We use the same values as above, for all the variables |
| ie.( 40574.21*(1+0.0075)^79)-(1200*((1+0.0075)^79-(1-0.02)^79)/(0.0075-(-0.02))) |
| 3319.53 |
| So, the answer--- o/s loan bal. after the 79th mthly. Pmt. Is |
| 3319.53 |
| (Answer) |
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