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A baseball (m= 149 g) approaches a bat horizontally at a speed of 40
A baseball (m= 149 g) approaches a bat horizontally at a speed of 40.2 m/s (90mi/h) and is hit straight back at a speed of 45.6 m/s (102 mi/h). If the ball is in contact with the bat for a time of 1.10 ms, what is the average force exerted on the ball by the bat? Neglecting the weight of the ball, since it is so much less than the force of the bat. Choose the direction of the incoming ball as the positive direction.
Expert Solution
Choose the direction of the incoming ball as the positive direction, then the initial speed v1=40.2m/s and the hi back speed is v2=-45.6m/s
F*t=m(v1-v2)
F*1.1=0.149*(40.2+45.6)
Solve the equation, we got:
F=11.6 Newton
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