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Homework answers / question archive / 1) A particle traveling around a circle at constant speed will experience an acceleration
1) A particle traveling around a circle at constant speed will experience an acceleration. - True
2. The test-mass is referred to as m and it hangs from the test-mass riser. - True
3. A particle travels 17 times around a 15-cm radius circle in 30 seconds. What is the average speed (in m/s) of the particle?- .5327 m/s
4. What measurements will be made to determine the magnitude of the test-mass centripetal acceleration?- items 3 and 6
(1) The mass of the test-mass.
(2) The velocity of the test-mass.
(3) The radius of the circular path.
(4) The mass of the hanging mass.
(5) The spring constant.
(6) The period of the orbital motion.
5. Before rotating the platform, the hanging mass is disconnected from the test mass and removed from the platform.- True
6. A particle in uniform circular motion requires a net force acting in what direction? - towards the center of the circle
7. The centripetal force acting on a particle is given byF = mv2/r. If the centripetal force and mass are kept constant, increasing the radius of the particle's circular path will mean that the particle's velocity must increase.- True
1 ans
basing on circular motion if paraticle moves in circular motion in constant speed it gives the acceleration
because at certain point velocity is changes
2 ans
true
because the test mass is reffered as m but it is hangs from test mass rasier becuse it is does give the correct periodic motion so it mass is found
3 ans
time t=30 s
radius r=15 cm
no of times rotation N=17
now we find the total distance
total distance =r(2*pi*N)
=15*10^-2*2*3.14*17
=16.014 m
the average velocity V=total distance/total time =16.014/30=0.5338 m/s
4 ans
yes it is correct
the magnitude of test mass of centripetal acceleration is determined by basing on radius of circular path
and period of the orbital motion
centripetal acceleration =V^2/r
5 ans
true
because if taken rotating the platform it contains test mass is give perfect oscillation
6 ans
if net force is always perpendicular to velocity so the net force is towards the centre of the circle
7 ans
true
because the velocity and radius is directly propertional to radius
