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Homework answers / question archive / Starting from the definition of Specific Enthalpy, ? = ? + ??, show that: ? ?? = ?−1 ? Explain the meaning of the word “Adiabatic” and give an example of non-adiabatic flow in the engine
?
??
= ?−1
?
End of Part A Continue to Part B
Part B
Answer any two questions from Part B
iii Calculate the temperature and pressure at the throat for the flow generated in part ii above.
Continued…
End of Part B. End of Question Paper
Formula Sheet – Aeroengines & rocket Science
ISA Table
H |
T |
P |
r |
a |
n |
m |
km |
K |
N.m-2 |
kg.m-3 |
m.s-1 |
m2.s-1 |
N.s.m-2 |
0 |
288.2 |
1.0133E+05 |
1.2252 |
340.3 |
1.4634E-05 |
1.7930E-05 |
1 |
281.7 |
8.9866E+04 |
1.1117 |
336.4 |
1.5837E-05 |
1.7607E-05 |
2 |
275.2 |
7.9480E+04 |
1.0065 |
332.5 |
1.7169E-05 |
1.7280E-05 |
3 |
268.7 |
7.0088E+04 |
0.9090 |
328.5 |
1.8647E-05 |
1.6950E-05 |
4 |
262.2 |
6.1616E+04 |
0.8190 |
324.5 |
2.0290E-05 |
1.6617E-05 |
5 |
255.7 |
5.3993E+04 |
0.7359 |
320.5 |
2.2122E-05 |
1.6280E-05 |
6 |
249.2 |
4.7153E+04 |
0.6594 |
316.4 |
2.4170E-05 |
1.5939E-05 |
7 |
242.7 |
4.1032E+04 |
0.5892 |
312.2 |
2.6466E-05 |
1.5593E-05 |
8 |
236.2 |
3.5571E+04 |
0.5248 |
308.0 |
2.9046E-05 |
1.5244E-05 |
9 |
229.7 |
3.0714E+04 |
0.4660 |
303.8 |
3.1955E-05 |
1.4891E-05 |
10 |
223.2 |
2.6408E+04 |
0.4123 |
299.4 |
3.5246E-05 |
1.4534E-05 |
11 |
216.7 |
2.2605E+04 |
0.3636 |
295.0 |
3.8980E-05 |
1.4172E-05 |
12 |
216.7 |
1.9308E+04 |
0.3105 |
295.0 |
4.5638E-05 |
1.4172E-05 |
13 |
216.7 |
1.6491E+04 |
0.2652 |
295.0 |
5.3434E-05 |
1.4172E-05 |
14 |
216.7 |
1.4085E+04 |
0.2265 |
295.0 |
6.2560E-05 |
1.4172E-05 |
15 |
216.7 |
1.2030E+04 |
0.1935 |
295.0 |
7.3246E-05 |
1.4172E-05 |
16 |
216.7 |
1.0275E+04 |
0.1653 |
295.0 |
8.5756E-05 |
1.4172E-05 |
17 |
216.7 |
8.7763E+03 |
0.1411 |
295.0 |
1.0040E-04 |
1.4172E-05 |
18 |
216.7 |
7.4959E+03 |
0.1206 |
295.0 |
1.1755E-04 |
1.4172E-05 |
19 |
216.7 |
6.4024E+03 |
0.1030 |
295.0 |
1.3763E-04 |
1.4172E-05 |
20 |
216.7 |
5.4684E+03 |
0.0879 |
295.0 |
1.6114E-04 |
1.4172E-05 |
1bar = 105 N/m2
Patm = 1.01325x105 Pa
Air density = 1.2252 kg/m3
? (??????) = ?° (???????) + 273 ????????? = ?????? + ??????
γ = 1.4, R= 287 J/kg.K, CP= 1004 J/kg K
γ = 1.3, CP= 1140 J/Kg K, R=283 J/Kg.K
The Lower Calorific Value of hydrocarbon aviation fuel: hPR= 45,000KJ/kg
Thermodynamics:
1 ??? = 100,000 ?? 1 ??? = 101,325 ??
Ideal Gas
?? = ??? ?? = ?? Polytropic process: ??? = ????????
Adiabatic process: ??? = ????????
Work Done
? = ∫?2 ???
?1
Isothermal:
Polytropic: ? = ?1?1−?2?2
?−1
?2
? = ?1?1?? ( )
?1
Specific Heat Capacities
??
= ??
??
??
= ??
??
? = ??
??
??
− ??
= ?
Non Flow Energy Equation
? − ? = ?? ? − ? = ??
Steady Flow Energy Equation
?? − ?? = ?? + ??? + ???
?? − ?? = ?? (? + ?2 + ??)
2
???
− ?? (? + ?2 + ??)
2
??
Where ? = ????????
?? = ??? ? = ? + ?? or ? = ? + ??
Second Law of Thermodynamics
2 ??
?? = ?2 − ?1 = ∫
1 ?
Gibbs Equation:
Isentropic Relationships:
??? = ?? − ??? = ?? + ???
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?2 =
?1
?2 ( )
?−1
|
|
?2 − ?1 = ???? (
?1
) − ? ?? (
?2
?1
) (Ideal Gas Only)
Thrust Equation:
? = (??0 + ??? )? − ??0?0 + (?? − ?0)??
Speed of Sound: ? = √???
Mach number: ? = ?
?
Total Temperature: ??
Isentropic Area Ratio:
Mass Flow Parameter:
= (1 + ?−1 ?2)
2
Subscript 1 refers to conditions before the shock and 2 to conditions after the shock.
![]() |
Propulsive efficiency:
![]() |
Thermal efficiency:
![]() |
Overall efficiency:
?? = ?? × ??
Effective Exhaust velocity:
??
???
=
?? ????
(?? − ??)??
? = ?? +
???
Specific Impulse: ???
= ?
?? ?
|
Orbital speed: ? = √?
??+?
Velocity increment:
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Massey, B.S., Mechanics of fluids, Spon press, 9th Edition, 2012
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