0.58744 x 10^-1 eV

= 0.058744 eV

[can be rounded to 0.59x10^-1eV = 0.059eV or 0.587x10^-1eV= 0.0587eV]

Since the electric and magnetic field are perpendicular , the forces due to both must be acting against each other. And since the electron is undeviated, net force on it must be zero . Hence the magnitudes of forces due to electric and magnetic fields must be equal .- 0 magnitude FE ( force by E field) = Eq - [basic formula E- Electric field 9 - charge magnitude of basic formula 1-7 charge ( force by magnetic field ) . = ay VBsina V - velocity - By magnetic field = q, VB sin 90 0 / 2 = 90 , given perpendicular 2 7Angle between = q, VB -3 V and B Using (2) and 3) in 1 => 9 / VB =) V - E ->4 B . '. KE = Imv . J 2 B

OV IT = I ev Lymy/E e 2 1. 60218 X10 19 where e -y charge of election Given e = 1. 60 21 8 x 10#9 C
- 31 X 9 . 10 9 39 x 10 X/0 . 2 3 X 10 3 given 1. 6 x 103 1. 60 21 8 X 10 -19 values = 0 . 58 7 4 4 x 10 #
ev

please see the attached file for complete answer