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Homework answers / question archive / How many moles of sodium acetate trihydrate is needed to prepare 100

How many moles of sodium acetate trihydrate is needed to prepare 100

Chemistry

How many moles of sodium acetate trihydrate is needed to prepare 100.00 mL of a buffer with a total buffer concentration of 0.110 mol/L?

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5.50 x 10-3 mol

Step-by-step explanation

For a buffer to reach its maximum buffer capacity (a measure of how effective a buffer is), the amount of its conjugate base must be equal to the amount of the weak acid. In the case of acetate buffer, the amount of sodium acetate trihydrate must be equal to the amount of acetic acid.

 

amount of total buffer = amount of sodium acetate trihydrate + amount of acetic acid

ntotal buffer = nsodium acetate trihydrate + nacetic acid

 

Because nsodium acetate trihydrate = nacetic acid for maximum buffer capacity,

ntotal buffer = 2 nsodium acetate trihydrate

 

The ntotal buffer can be determined by multiplying the molarity (in mol/L) of the buffer by its volume (in L). 

ntotal buffer = Mbuffer x Vbuffer = 0.110 mol/L x 0.1000 L = 0.0110 mol

 

Use the calculated ntotal buffer to solve for nsodium acetate trihydrate.

ntotal buffer = 2 nsodium acetate trihydrate

nsodium acetate trihydrate = ntotal buffer / 2 = 0.0110 mol / 2 = 5.50 x 10-3 mol