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Homework answers / question archive / How many moles of sodium acetate trihydrate is needed to prepare 100
How many moles of sodium acetate trihydrate is needed to prepare 100.00 mL of a buffer with a total buffer concentration of 0.110 mol/L?
5.50 x 10-3 mol
Step-by-step explanation
For a buffer to reach its maximum buffer capacity (a measure of how effective a buffer is), the amount of its conjugate base must be equal to the amount of the weak acid. In the case of acetate buffer, the amount of sodium acetate trihydrate must be equal to the amount of acetic acid.
amount of total buffer = amount of sodium acetate trihydrate + amount of acetic acid
ntotal buffer = nsodium acetate trihydrate + nacetic acid
Because nsodium acetate trihydrate = nacetic acid for maximum buffer capacity,
ntotal buffer = 2 nsodium acetate trihydrate
The ntotal buffer can be determined by multiplying the molarity (in mol/L) of the buffer by its volume (in L).
ntotal buffer = Mbuffer x Vbuffer = 0.110 mol/L x 0.1000 L = 0.0110 mol
Use the calculated ntotal buffer to solve for nsodium acetate trihydrate.
ntotal buffer = 2 nsodium acetate trihydrate
nsodium acetate trihydrate = ntotal buffer / 2 = 0.0110 mol / 2 = 5.50 x 10-3 mol