Fill This Form To Receive Instant Help
Fill This Form To Receive Instant Help
Homework answers / question archive / The mass of tin deposited is 1
The mass of tin deposited is 1.1 g.
The steps involved are: 1. Write the balanced equation. 2. Use conversion factors to convert mass of Ag → moles of Ag → moles of Sn → mass of Sn
Step 1
The balanced equation for a galvanic cell is
2 × [Ag? + e? → Ag]; ##E°## = +0.80 V 1 ×[Sn →Sn²? + 2e?]; ##E°## = +0.14 V
2Ag? + Sn → 2Ag + Sn²?; ##E°## = +0.94 V
This equation tells you that, when you force electricity between two cells in series, the moles of tin deposited are twice the moles of silver.
Step 2
Mass of Sn = 2.0 g g Ag × ##(1"mol Ag")/(107.9"g Ag") × (1"mol Sn")/(2"mol Ag") × (118.7"g Sn")/(1"mol Sn")## = 1.1 g Sn (2 significant figures)
