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Homework answers / question archive / University of Florida ORGO 215 Package title: Solomons Test Bank Course Title: Solomons 11e Chapter Number: 8 1)What is the major product of the following reaction sequence? Br 1
University of Florida
ORGO 215
Package title: Solomons Test Bank
Course Title: Solomons 11e Chapter Number: 8
1)What is the major product of the following reaction sequence?
2a. OsO4, pyridine 2b. H2O, NaHSO3
OH
HO
A)
OH
HO
B)
Br
O
+
+ enantiomer
O
O |
HO OH + enantiomer
A)
HO
HO + enantiomer
B)
O
OH
HO
O
H
O |
OH
E)
HO O
O OH
I II III
IV V
OH
+ enantiomer
O
HO
O
H
O
H
H
![]() |
CO2H
A)
SMe2
OH |
C) OH
+ CO2
+ enantiomer
CHO
D)
+ HCHO
E) None of these choices.
i. O3
? ii. Zn, HOAc O
H
+ H O
R
HO
A)
O
(Racemic)
B)
O
+ CO2
C)
O
+ HCHO
D)
E) More than one of these choices.
Z 1) O3
2) Zn, HOAc
O O O
2HCH + CH3CCH2CH
O |
O |
H
IV V
O
O
I II III
IV V
isomers of heptene. The reaction product in each case would consist of:
CH3
CH3CH=C-CHCH2CH3
CH3
(cis or trans)
CH3CH2C=CCH3
CH3
(cis or trans)
CH2=CCH2CHCH2CH3
CH2 CH3CH2CCHCH2CH3
CH3 CH3CH2CHCHCH=CH2
O
O
The structure of C is:
I II III
![]() |
![]() |
IV V
Br |
2a. KMnO4, NaOH, heat 2b. H3O+
OH
+ enantiomer
OH
A)
O
H
H
B) O
O
C)
O
HO
D)
E) O
O
OH
O
+ CO2
1. t-BuOK, t-BuOH
Cl
2a. O3, CH2Cl2, -78 oC
2b. Me2S
O
A)
H
O |
OH
OH |
C)
OH
+ HCHO
O
+ enantiomer
2a. O3, CH2Cl2, -78 oC
2b. Me2S
OH |
+ enantiomer
D)
+ HCHO
+ CO2
OH
E) More than one of these choices.
2 Cl2 ?
Cl
Cl
Cl
I II
Cl
Cl |
Cl |
III
Cl Cl Cl
Cl
IV V
2 HCl
?
Cl
Cl
I II
Cl
Cl
III
Cl Cl Cl
Cl
IV V
I II
2-methyl-4,4-dichloroheptane 2-methyl-3,4-dichloroheptane III IV
2-methyl-3-chloroheptene V
A) (1) HBr; (2) NaOC2H5
B) (1) Br2; (2) NaOC2H5
C) (1) Br2; (2) H2O
E) (1) HBr; (2) H2SO4
Cl
Br
A)
Br
Cl
B)
Cl Br
C)
Br |
D)
OH |
B)
C)
CHO
CO2H
+ HCHO
+ CO2
CO2H
D)
E) None of these choices.
A)
B)
C)
D)
E)
be:
Question type: True/False
42) p bonds are quite susceptible to reaction with electron-seeking reagents, also referred to as
.
HCl
HI I
+ |
fast |
+ |
+ |
|
I |
in the final product:
O |
OH
Eucalyptol
Question type: fill-in-the-blank
NaOC2H5/C2H5OH, heat BH3, THF
H2O2, OH-
Br H
H
NaOC2H5
E-3-methyl-2-hexene
H3C H
(2R,3R)
C2H5OH
(E2: anti
elimination)
CH3
Hydroboration/oxidation: overall
Anti-Markovnikov,
syn addition of H2O
H OH
H3C H
HO H
+
H CH3
(2S,3R) (2R,3S)
3-methyl-2-pentanol
reaction to an alkene, the product is always formed as a racemic mixture. Why is that?
Answer: stereospecific
Question type: Essay
CH(CH3)2
CH(CH3)2
CH(CH3)2
CH(CH3)2
Br2, H2O ?
Zn, CH I H H
2 2
H + H
CH(CH3)2 CH(CH3)2
O O
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