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Homework answers / question archive / Qatar University MAGT 304 ch14 1)In one-way ANOVA, the amount of total variation that is unexplained is measured by the: a
Qatar University
MAGT 304
ch14
1)In one-way ANOVA, the amount of total variation that is unexplained is measured by the:
a. |
sum of squares for treatments. |
b. |
sum of squares for error. |
c. |
total sum of squares. |
d. |
degrees of freedom. |
2. The test statistic of the single-factor ANOVA equals:
a. |
sum of squares for treatments / sum of squares for error. |
b. |
sum of squares for error / sum of squares for treatments. |
c. |
mean square for treatments / mean square for error. |
d. |
mean square for error / mean square for treatments. |
3. In a single-factor analysis of variance, MST is the mean square for treatments and MSE is the mean square for error. The null hypothesis of equal population means is rejected if:
a. |
MST is much smaller than MSE. |
b. |
MST is much larger than MSE. |
c. |
MST is equal to MSE. |
d. |
None of these choices. |
4. Which of the following is not a required condition for one-way ANOVA?
a. |
The sample sizes must be equal. |
b. |
The populations must all be normally distributed. |
c. |
The population variances must be equal. |
d. |
The samples for each treatment must be selected randomly and independently. |
5. The analysis of variance is a procedure that allows statisticians to compare two or more population:
a. |
means. |
b. |
proportions. |
c. |
variances. |
d. |
standard deviations. |
6. The distribution of the test statistic for analysis of variance is the:
a. |
normal distribution. |
b. |
Student t-distribution. |
c. |
F-distribution. |
d. |
None of these choices. |
7. In a one-way ANOVA, error variability is computed as the sum of the squared errors, SSE, for all values of the response variable. This variability is the:
a. |
the total variation. |
b. |
within-treatments variation. |
c. |
between-treatments variation. |
d. |
None of these choices. |
8. In the one-way ANOVA where there are k treatments and n observations, the degrees of freedom for the F-statistic are equal to, respectively:
a. |
n and k. |
b. |
k and n. |
c. |
nk and k1. |
d. |
k1 and nk. |
9. In the one-way ANOVA where k is the number of treatments and n is the number of observations in all samples, the degrees of freedom for treatments is given by:
a. |
k1 |
b. |
nk |
c. |
n1 |
d. |
nk + 1 |
10. In ANOVA, the F-test is the ratio of two sample variances. In the one-way ANOVA (completely randomized design), the variance used as a numerator of the ratio is:
a. |
mean square for treatments. |
b. |
mean square for error. |
c. |
total sum of squares. |
d. |
None of these choices. |
11. In a completely randomized design for ANOVA, the numerator and denominator degrees of freedom are 4 and 25, respectively. The total number of observations must equal:
a. |
24 |
b. |
25 |
c. |
29 |
d. |
30 |
12. The number of degrees of freedom for the denominator in one-way ANOVA test involving 4 population means with 15 observations sampled from each population is:
a. |
60 |
b. |
19 |
c. |
56 |
d. |
45 |
13. The value of the test statistic in a completely randomized design for ANOVA is F = 6.29. The degrees of freedom for the numerator and denominator are 5 and 10, respectively. Using an F table, the most accurate statements to be made about the p-value is that it is:
a. |
greater than 0.05 |
b. |
between 0.025 and 0.050. |
c. |
between 0.010 and 0.025. |
d. |
between 0.001 and 0.010. |
14. In one-way ANOVA, the term
refers to the:
a. |
sum of the sample means. |
b. |
sum of the sample means divided by the total number of observations. |
c. |
sum of the population means. |
d. |
weighted average of the sample means. |
15. For which of the following is not a required condition for ANOVA?
a. |
The populations are normally distributed. |
b. |
The population variances are equal. |
c. |
The samples are independent. |
d. |
All of these choices are required conditions for ANOVA. |
16. One-way ANOVA is applied to independent samples taken from three normally distributed populations with equal variances. Which of the following is the null hypothesis for this procedure?
a. |
1 + 2 + 3 = 0 |
b. |
1 + 2 + 3 0 |
c. |
1 = 2 = 3 = 0 |
d. |
1 = 2 = 3 |
17. In the one-way ANOVA where k is the number of treatments and n is the number of observations in all samples, the number of degrees of freedom for error is:
a. |
k1 |
b. |
nk |
c. |
n1 |
d. |
nk + 1 |
18. How does conducting multiple t-tests compare to conducting a single F-test?
a. |
Multiple t-tests increases the chance of a Type I error. |
b. |
Multiple t-tests decreases the chance of a Type I error. |
c. |
Multiple t-tests does not affect the chance of a Type I error. |
d. |
This comparison cannot be made without knowing the number of populations. |
19. In one-way analysis of variance, between-treatments variation is measured by the:
a. |
SSE |
b. |
SST |
c. |
SS(Total) |
d. |
standard deviation |
20. One-way ANOVA is applied to independent samples taken from four normally distributed populations with equal variances. If the null hypothesis is rejected, then we can infer that
a. |
all population means are equal. |
b. |
all population means differ. |
c. |
at least two population means are equal. |
d. |
at least two population means differ. |
21. Consider the following partial ANOVA table:
Source of Variation |
SS |
df |
MS |
F |
Treatments |
75 |
* |
25 |
6.67 |
Error |
60 |
* |
3.75 |
|
Total |
135 |
19 |
|
|
The numerator and denominator degrees of freedom for the F-test (identified by asterisks) are
a. |
4 and 15 |
b. |
3 and 16 |
c. |
15 and 4 |
d. |
16 and 3 |
22. Consider the following ANOVA table:
Source of Variation |
SS |
df |
MS |
F |
Treatments |
4 |
2 |
2.0 |
0.80 |
Error |
30 |
12 |
2.5 |
|
Total |
34 |
14 |
|
|
The number of treatments is
a. |
13 |
b. |
5 |
c. |
3 |
d. |
12 |
23. In one-way analysis of variance, within-treatments variation is measured by:
a. |
sum of squares for error. |
b. |
sum of squares for treatments. |
c. |
total sum of squares. |
d. |
standard deviation. |
24. Consider the following ANOVA table:
Source of Variation |
SS |
df |
MS |
F |
Treatments |
128 |
4 |
32 |
2.963 |
Error |
270 |
25 |
10.8 |
|
Total |
398 |
29 |
|
|
The total number of observations is:
a. |
25 |
b. |
29 |
c. |
30 |
d. |
32 |
25. In one-way analysis of variance, if all the sample means are equal, then the:
a. |
total sum of squares is zero. |
b. |
sum of squares for error is zero. |
c. |
sum of squares for treatments is zero. |
d. |
sum of squares for error equals sum of squares for treatments. |
26. Which of the following components in an ANOVA table is not additive?
a. |
Sum of squares |
b. |
Degrees of freedom |
c. |
Mean squares |
d. |
All of these choices are additive. |
27. In which case can an F-test be used to compare two population means?
a. |
For one tail tests only. |
b. |
For two tail tests only. |
c. |
For either one or two tail tests. |
d. |
None of these choices. |
28. The F-test statistic in a one-way ANOVA is equal to:
a. |
MST/MSE |
b. |
SST/SSE |
c. |
MSE/MST |
d. |
SSE/SST |
29. The numerator and denominator degrees of freedom for the F-test in a one-way ANOVA are, respectively,
a. |
(nk) and (k1) |
b. |
(k1) and (nk) |
c. |
(kn) and (n1) |
d. |
(n1) and (kn) |
30. Which of the following statements is false?
a. |
F = t2 |
b. |
The F-test can be used instead of a two tail t-test when you compare two population means. |
c. |
Doing three t-tests is statistically equivalent to doing one F-test when you compare three population means. |
d. |
All of these choices are true. |
31. Which of the following statements about multiple comparison methods is false?
a. |
They are to be use once the F-test in ANOVA has been rejected. |
b. |
They are used to determine which particular population means differ. |
c. |
There are many different multiple comparison methods but all yield the same conclusions. |
d. |
All of these choices are true. |
32. When the objective is to compare more than two populations, the experimental design that is the counterpart of the matched pairs experiment is called a:
a. |
completely randomized design. |
b. |
one-way ANOVA design. |
c. |
randomized block design. |
d. |
None of these choices. |
33. In the randomized block design for ANOVA, where k is the number of treatments and b is the number of blocks, the number of degrees of freedom for error is:
a. |
kb |
b. |
nkb + 1 |
c. |
kb1 |
d. |
None of these choices. |
34. Which of the following is false regarding SSB?
a. |
SSB stands for sum of squares for blocks. |
b. |
SSB can help to reduce SSE. |
c. |
SSB can help make it easier to determine whether differences exist between the treatment means. |
d. |
All of these choices are true. |
35. The primary interest of designing a randomized block experiment is to:
a. |
reduce the variation among blocks. |
b. |
increase the between-treatments variation to more easily detect differences among the treatment means. |
c. |
reduce the within-treatments variation to more easily detect differences among the treatment means. |
d. |
None of these choices. |
36. The randomized block design with exactly two treatments is equivalent to a two-tail:
a. |
independent samples z-test. |
b. |
independent samples equal-variances t-test. |
c. |
independent samples unequal-variances t-test. |
d. |
matched pairs t-test. |
37. In the randomized block design ANOVA, the sum of squares for error equals:
a. |
SS(Total)SST |
b. |
SS(Total)SSB |
c. |
SS(Total)SSTSSB |
d. |
None of these choices. |
38. A randomized block design with 4 treatments and 5 blocks produced the following sum of squares values: SS(Total) = 1,951, SST = 349, SSE = 188 . The value of SSB must be:
a. |
1,414 |
b. |
537 |
c. |
1,763 |
d. |
1,602 |