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A university spent $2 million to install solar panels atop a parking garage
A university spent $2 million to install solar panels atop a parking garage. These panels will have a capacity of 700 kilowatts (kW) and have a life expectancy of 20 years. Suppose that the discount rate is 10%, that electricity can be purchased at $0.20 per kilowatt-hour (kWh), and that the marginal cost of electricity production using the solar panels is zero.
Hint: It may be easier to think of the present value of operating the solar panels for 1 hour per year first.
Approximately how many hours per year will the solar panels need to operate to enable this project to break even?
1,677.99
2,684.78
671.20
If the solar panels can operate only for 1,510 hours a year at maximum, the project break even. (Would or would not)
Continue to assume that the solar panels can operate only for 1,510 hours a year at maximum.
In order for the project to be worthwhile (i.e., at least break even), the university would need a grant of at least (120,138.60, 320,369.60,200,231.00,240,277.20)
Expert Solution
1) For a break even it would needs to run for ($2.0 million / $1,191.90) = 1,677.99 hours per year.
2) So, If the solar panels can operate only for 1,510 hours a year at maximum, the project would not break even.
3) If we should take in consideration electricity for an efficient system of 1,510 hours we will have a PV of ($1,191.90*1510)
=$1799767.37
($2000,000 - $1799767.37) = $200,231
So, This is $200,231 short of $2 million.
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