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Homework answers / question archive / Figure 1) shows the velocity graph of a 69 kg passenger in an elevator
Figure 1) shows the velocity graph of a 69 kg passenger in an elevator.no title providedWhat is the passenger's apparent weight at t=1.0s?What is the passenger's apparent weight at t=5.0s?What is the passenger's apparent weight at t=9.0s?
Apparent weight = mg + ma = m(g+a)
where a = acceleration = slope of velocity-time graph.
1. a = 8/2 = 4 m/s^2
Apparent weight = 69 * (9.8+4) = 952.2 N
2. a = 0 m/s^2
Apparent weight = 69 * (9.8+0) = 676.2 N
3. a =- 8/4 = -2 m/s^2
Apparent weight = 69 * (9.8-2) = 538.2 N
