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a) What is the amplitude of the oscillation shown in (Figure 1)? b) What is the frequency of the oscillation shown in the figure? c) What is the phase constant of the oscillation shown in the figure? Suppose that −180? ≤ ?0 ≤180?

Physics Jan 21, 2021

a) What is the amplitude of the oscillation shown in (Figure 1)?

b) What is the frequency of the oscillation shown in the figure?

c) What is the phase constant of the oscillation shown in the figure? Suppose that −180? ≤ ?0 ≤180?.

x(cm) 10 t (s) 2 10

Expert Solution

Amplitude= Maximun displacement from mean point

Amplitude = 10 cm

=0.1 m (ANS)

(b) Frequncy = Number of vibration per second.

In given diagram to complet one cycle or one vibration it takes 4 s.

requency = 1/4 Hz

or 0.25 Hz (ANS)

(c)

We have equation for displacement at time t. $\phi$ is phase constant.

$x(t)=Acos(\omega t+\phi )$

for t=0

,we have x(t)= =-0.05m (from figure) , A =0.1 m

$-0.05=0.1\times cos(\omega \times 0+\phi )$

$cos\phi = \frac{-0.05}{0.1}$

$\phi$ =120⁰ (ANS)

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