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What is the net ionic equation of the reaction of BeCl2 with NaOH? Express you answer as a chemical equation including phases.

pur-new-sol

Part A :

The balanced chemical reaction between BeCl2 & NaOH solutions is :

BeCl₂ (aq) + 2NaOH (aq) $\rightarrow$ Be(OH)₂(s)+2NaCl(aq)

Total ionic equation is obtained by writting the ions in the aqueous form

Be²⁺ (aq) + 2Cl^- (aq) + 2Na⁺ (aq) + 2OH^- (aq) $\rightarrow$ Be(OH)₂(s) + 2Na⁺(aq) + 2Cl^-(aq)

Net ionic equation is obtained by cancelling the common ions on both sides we get

Be²⁺ (aq) + 2Cl^- (aq) + 2Na⁺ (aq) + 2OH^- (aq) $\rightarrow$ Be(OH)₂(s) + 2Na⁺(aq) + 2Cl^-(aq)

Be²⁺ (aq) + 2OH^- (aq) $\rightarrow$ Be(OH)₂(s)

This is the balaned net ionic equation

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Part B :

The balanced chemical reaction between MgSO₄ & Ba(NO₃)₂ solutions is :

MgSO₄ (aq)+ Ba(NO₃)₂ (aq) $\rightarrow$ BaSO₄(s) + Mg(NO₃)₂ (aq)

Total ionic equation is obtained by writting the ions in the aqueous form

Mg²⁺ (aq) + SO₄^2- (aq) + Ba²⁺ (aq) + 2NO₃^- (aq) $\rightarrow$ BaSO₄(s) + Mg²⁺ (aq) + 2NO₃^- (aq)

Net ionic equation is obtained by cancelling the common ions on both sides we get

Mg²⁺ (aq) + SO₄^2- (aq) + Ba²⁺ (aq) + 2NO₃^- (aq) $\rightarrow$ BaSO₄(s) + Mg²⁺ (aq) + 2NO₃^- (aq)

SO₄^2- (aq) + Ba²⁺ (aq) $\rightarrow$ BaSO₄(s)

This is the balaned net ionic equation