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Homework answers / question archive / (20%) Problem 3: Water flows through a water hose at a rate of Q1 = 680 cm/s, the diameter of the hose is du = 2

(20%) Problem 3: Water flows through a water hose at a rate of Q1 = 680 cm/s, the diameter of the hose is du = 2

Physics

(20%) Problem 3: Water flows through a water hose at a rate of Q1 = 680 cm/s, the diameter of the hose is du = 2.2 cm. A nozzle is attached to the water hose. The water leaves the nozzle at a velocity of V2 = 9.2 m/s. D A 17% Part (a) Enter an expression for the cross-sectional area of the hose, Aj, in terms of its diameter, d. A1 = 1 Grade Summary Deductions Potential 100% 096 HOME ( ) 7 8 I ^^ ^1 4 5 * 1 2 + - 0 VO BACKSPACE 9 6 3 . DEL Submissions Attempts remaining: 20 (3% per attempt) detailed view P vi Q V2 END CLEAR Submit Hint Feedback I give up! Hints: 2% deduction per hint. Hints remaining: 1 Feedback: 2% deduction per feedback A 17% Part (b) Calculate the numerical value of Aj, in square centimeters. A 17% Part (C) Enter an expression for the speed of the water in the hose, vi, in terms of the volume flow rate Q, and cross-sectional area Aj. 4 17% Part (d) Calculate the speed of the water in the hose, vi in meters per second. A 17% Part (e) Enter an expression for the cross-sectional area of the nozzle, A2, in terms of V1, V2 and Aj. 17% Part (f) Calculate the cross-sectional area of the nozzle, Az in square centimeters.

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problem 3)

part a) A1 = pi*d1^2/4 <<<<<<<<-----------Answer

part b) A1 = pi*2.2^2/4

= 3.80 cm^2 <<<<<<<<-----------Answer

part c) Q1 = A1*v1

==> v1 = Q1/A1 <<<<<<<<-----------Answer

part d)

v1 = 680/3.80

= 179 cm/s

= 1.79 m/s   <<<<<<<<-----------Answer

part e) using continuty equation, A2*v2 = A1*v1

A2 = A1*v1/v2 <<<<<<<<-----------Answer

part f) A2 = 3.80*1.79/9.2
= 0.739 cm^2 <<<<<<<<-----------Answer