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Homework answers / question archive / a What is the rate law for the uncatalyzed reaction? a
a What is the rate law for the uncatalyzed reaction? a. \rm rate={\it k}[Ce^{4+}]^2[Tl^+] b. \rm rate={\it k}[Ce^{4+}][Tl^+] c. \rm rate={\it k}[Ce^{4+}] d. \rm rate={\it k}[Ce^{4+}][Tl^+]^2 e. \rm rate={\it k}[Ce^{4+}]^2[Tl^+]^2 f. \rm rate={\it k}[Tl^+] Part B If the uncatalyzed reaction occurs in a single elementary step, why is it a slow reaction? Check all that apply. Check all that apply. a. The reaction requires the collision of three particles with the correct energy and orientation. b. The probability of an effective three-particle collision is low. c. All reactions that occur in one step are slow. d. The transition state is low in energy. Part C The catalyzed reaction is first order in \rm [Ce^{4+}] and first order in \rm [Mn^{2+}]. Which of the steps in the catalyzed mechanism is rate determining? a. \rm Ce^{4+}(aq)+Mn^{2+}(aq)\rightarrow Ce^{3+}(aq) + Mn^{3+}(aq) b. \rm Ce^{4+}(aq)+Mn^{3+}(aq)\rightarrow Ce^{3+}(aq)+Mn^{4+}(aq) c. \rm Mn^{4+}(aq)+Tl^+(aq)\rightarrow Mn^{2+}(aq)+Tl^{3+}(aq) Based on their available oxidation states, rank the following metals on their ability to catalyze this and other oxidation-reduction reactions. Rank from best to worst catalyst. To rank items as equivalent, overlap them. Manganese , titanium and vanadium
PART B )
A and C is the answers
Part A)
You cant simply create a rate law from a chemical equation.
The rate law can only be determined by experiments.
There are various ways to determine the rate law by experiment, One way is by altering the concentration of the reactants and determine the effect on the rate of the reaction. By doing so, the order of reaction with respect to the reactant can be asertained.
Repeating the same process with other reactant and finally the overall order of reaction can be determined.
After the overall order of reaction is determined, then only the rate law can be established.
PART C)
The answer is Manganese, then Vanadium, and the Titanium