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A 15
A 15.0mL sample of NaCl solution has a mass of 15.78 g. Afterthe NaCl solution is evaporated to dryness, the dry salt residuehas a mass of 3.26g. Calculate the following concentrations for theNaCl solution.
a. % (m/m)
b. % (m/v)
c. molarrity (M)
Expert Solution
Answer:
volume of thesolution = 15.0 mL
mass of the solution =15.78 g
mass of the solute(NaCl) = 3.26 g
∴ % m/m = (3.26 g / 15.78g ) *100
= 20.65 %
% m /v = ( 3.26 g / 15.0 mL ) * 100
= 21.73 %
Number of moles of the solute = 3.26 g / 58.44g/mol
=0.055 mol
volume of the solution = 15.0 mL = 0.015L
∴ molarity of the solution = 0.055 mol / 0.015L
= 3.66 M
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