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A 15

Chemistry

A 15.0mL sample of NaCl solution has a mass of 15.78 g. Afterthe NaCl solution is evaporated to dryness, the dry salt residuehas a mass of 3.26g. Calculate the following concentrations for theNaCl solution.

a. % (m/m)

b. % (m/v)

c. molarrity (M)

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Answer:

volume of thesolution = 15.0 mL

      mass of the solution =15.78 g

      mass of the solute(NaCl)   = 3.26 g

         ∴ % m/m = (3.26 g / 15.78g ) *100

                          = 20.65 %

             % m /v = ( 3.26 g / 15.0 mL ) * 100

                          = 21.73 %

          Number of moles of the solute = 3.26 g / 58.44g/mol

                                                           =0.055 mol

            volume of the solution = 15.0 mL = 0.015L

            ∴ molarity of the solution = 0.055 mol / 0.015L

                                                      = 3.66 M