Calculate the standard enthalpy of formation (ΔH?f) for nitroglycerin

Chemistry Jan 07, 2021

Calculate the standard enthalpy of formation (ΔH?f) for nitroglycerin.

The explosive nitroglycerin (C3H5N3O9) decomposes rapidly upon ignition or sudden impact according to the following balanced equation:
4C3H5N3O9(l)→12CO2(g)+10H2O(g)+6N2(g)+O2(g)ΔH?rxn=−5678kJ

Expert Solution

4C3H5N3O9(l)→12CO2(g)+10H2O(g)+6N2(g)+O2(g)

Hprocucts = 12*CO2 + 10*H2O + 6*N2 + O2 = 12*CO2 + 10*H2O +0 +0

Hreactants = 4*Hnitro

Hrxn = Hproducts - Hreactants

-5678 = 12*CO2 + 10*H2O -(4*Hnitro)

4H Nitro = 12*CO2 + 10*H2O + 5678

4H Nitro = 12*-393.509 + 10*-241.818 + 5678

Hnitro= (-1462.288)/4 = -365.572 kJ/mol

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