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Homework answers / question archive / What is the magnitude of the electric force on charge A in (Figure 1) ?
What is the magnitude of the electric force on charge A in (Figure 1) ?
Note that by Coulomb's Law,
F = kq1q2/r^2
where
k = 8.99E9 Nm^2/kg^2
q1, q2 = the two interacting charges
r = the distance of separation of the two charges
Thus, for force of B on A points to the right, as opposite charges attract.
qA = 1.0E-9 C
qB = -1.0E-9 C
r = 0.01 m
Thus,
F(B on A) = 8.99E-5 N
Now, for force of C on A points to the left, as like charges repel.
Thus, as
qA = 1.0E-9 C
qC = 4.0E-9 C
r = 0.02 m
F(C on A) = -8.99E-5 N [the negative sign because it is to the left]
Thus,
Fnet (A) = F(B on A) + F(C on A)
Fnet (A) = 0.00 N [ANSWER]