Draw the substitution product formed in the following reaction:  CH3  CH3  H2O   

1.Explanation | Hint for next step

Bromoalkane acts as electrophile and the electrophilic center of bromoalkane is highlighted using a circle. The circled carbon atom is then attached to more electronegative bromine atoms and gets a partial positive charge and is electron deficient. Water molecules act as nucleophiles.

2.Explanation | Common mistakes

The bromide ion is a good leaving group. The lone pair on oxygen attacks the electrophilic carbon and the bromide ion leaves as the leaving group. The oxygen atom bears a positive charge on it. The bromide ion abstracts a proton from the water molecule to neutralize the charges.

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