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Homework answers / question archive / A 6
A 6.82 g sample of potassium chlorate was decomposed according to the following equation:
2 KClO3 → 2 KCl + 3 O2
How many moles of oxygen are formed?
Answer
Moles of O2 formed = 0.083475 moles
Calculation
Given
mass = 6.82g
2 KClO3 → 2 KCl + 3 O2
Mole ratio
2 -----------> 2 : 3
Finding moles
Mole of KClO3 = mass/MM = 6.82/122.55 = 0.05565 moles
Mole of KCL = 0.05565 moles (Same mole ratio as KClO3)
mole of O2 = 0.05565* 3/2 = 0.083475 moles
Moles of O2 formed = 0.083475 moles
