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Homework answers / question archive / Error Analysis ~ Project Name: ___________ Potential Credits: /20 Using a pencil, answer the following questions
Error Analysis ~ Project Name: ___________
Potential Credits: /20
Using a pencil, answer the following questions. The lab is marked based on clarity of responses, completeness, neatness, and accuracy. Do your best! Please ensure that any data measured (or recorded) includes the appropriate number of significant digits (only one uncertain digit).
The purpose of this activity is to introduce yourself to the mathematical rules surrounding error analysis. By the end of this activity you will be familiar with absolute error and relative error. You will be able to determine the range of error in your final calculation by simply determining the minimum and maximum possible values based on uncertainties in measurements (given). You will then use this range to determine the mathematical rule that will be used from this point on to determine overall uncertainties in your labs and calculations.
If you finish this activity ALONG WITH the first error analysis lab in the next unit, you will be eligible to include error analysis as part of your lab write-up for any data-based projects. This will provide you an additional 5 points (maximum) for each lab. Eligible projects will be represented in green in the Summary of Projects table presented in each unit.
Each section will present the general rule that will guide you through the questions following. Work in pencil and be sure to check your answers as you go.
Absolute error is the actual value of the error in physical units. For example, let's say you managed to measure the length of your cat, L, to be 42cm with a precision 4cm. This means that your cat's length might be as small as (42-4)cm = 38cm, and as large as (42+4)cm = 46cm
The convention for reporting your result with an absolute error would be
L = 42cm ±4cm Where ±4cm represents the absolute error.
Notice that the measurement and the absolute error will always have the same number of decimal places. In other words, we can't write L = 41.94cm ±4cm since the error shows less precision than the measurement. We must round to the same decimal place as the error so that we get L = 42cm ±4cm. If our absolute error was only was ±0.2cm we would round to one decimal place as follows; 41.9cm ±0.2cm
Absolute error will always have the same units as the actual measurement. In general, the absolute error will always be rounded to include only one significant figure or the same number of decimal places as the answer expressed with the correct number of significant figures)
Relative error is simply the absolute error writen as a percentage of the measured value. In other words:
Relative error = (absolute error)/(measured value) x100%
For the cat above we could determine the relative error as follows:
4cm/42cm x 100% = 9.5% = 10%
We would write this (in terms of relative error) as
L = 42cm ±10% Questions:
Imagine you measure around the perimeter of the triangle below and obtain the following measurements:
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a |
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54 |
± |
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5 |
cm |
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b |
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= |
52 |
± |
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cm |
3 |
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c |
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= |
78 |
± |
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6 |
cm |
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a. |
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What is the largest possible perimeter based on your measurements? Show work clearly. |
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ans. 198 cm |
) |
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Rule for addition and subtraction: The absolute error of the result is the sum of the absolute errors of the original quantities. Remember, even if you subtract two quantities you still add their absolute errors.
What would the best value of the perimeter be (include the absolute error or tolerance)? What is the least possible value of the perimeter of the computer monitor to the nearest ten?
Imagine you measure the height and the base of the triangle below as shown:
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h |
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= |
45 |
± |
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3 |
cm |
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b |
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= |
78 |
± |
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6 |
cm |
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Show all work: |
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h = _________________________
b= _________________________
(hint: you may average out your two tolerances based on the smallest and largest values)
Rule for multiplication and division: The relative error of the result is the sum of the relative errors of the original quantities.
(ans: 40 cm2 ± 16%)
(ans: 40 cm2 ± 7 cm2)
(ans: 54 cm3 ± 47% or ± 26 cm3)
V = _____________ mm3 ±__________ mm3
(ans: 1.2x105 mm3 ± 8% or ± 0.1x105 mm3. Note: we always round the absolute error to the same decimal place as the answer with the correct sig figs)
b. the density of the block
ρ = ___________________ kg/mm3 ±___________ kg/mm3
(ans: 1.3x10-5 mm3 ± 14% or ± 0.2x10-5 cm3
Bill measures the radius of a circle to be 15.0 mm ±0.4 mm. He needs to determine the circumference of this circle along with its overall uncertainty.
Using c = 2πr determine: (show all work and keep a few decimal places for this exercise)
Rule for multiplying or dividing by a constant(s). When multiplying by a constant(s), the absolute error is multiplied by the same constant(s).
Or…
2.67%)
Rule for multiplying or dividing by a constant(s). The relative error overall is the same as it was for all the measurements involved in the calculations.
1. The top of a cylinder has a radius of r = (0.050 ± 0.005)cm. The height of the cylinder is h = (0.17 ± 0.01)cm. Determine
SA = 2πrh
Bill is measuring the period of motion for a mass on a spring. He measures the mass to be m = 0.150kg ± 0.002kg. Eventually, to determine the overall period of the spring mass oscillator, he
must determine
0.387 ± 0.0026
)
Rule for raising a number to a power of n: When a number is raised to a power of n, the relative error is the multiplied by n.
V = _______________ cm3 ± ___________ %
V = ______________ cm3 ± __________ cm3
x = _____________ m ± ___________ %
x = ______________ m ± __________ m
r = _____________ m ± ___________ %
r = ______________ m ± __________ m
You will rarely be confronted with an equation that simply follows one of the rules above. More often than not you will be required to determine the overall error for an equation that utilizes a combination of the rules above.
Calculate the value of the quantity X and its maximum error ±x from the measured values of a, b and c in each of the following:
X =6a + 4b |
a =40 ± 2 |
b =20 ± 2 |
For the above equation we see multiplication combined with addition.
Step 1: Get the value of X (without errors): We simply substitute in for a and b
X = 6(40) + 4(20) = 320
Step 2: Determine the relative error for each value:
a: 2/40 x 100% = 5% b: 2/20 x 100% = 10%
Step 3: Maintaining the same "order of operation" we deal with the multiplication first (relative error). Let's do each term separately.
6a = 6(40) = 240 ± 5% convert to absolute error = 240 ± 12 4b = 4(20) = 80 ± 10% convert to absolute error = 80 ± 8
Step 4: Now we can deal with the addition of the first term (6a) to the second term (4b).
Since this is adding/subtracting we will switch to absolute error.
(240 ± 12) + (80 ± 8) = 320 ± 20 (where we simply add the absolute errors)
Therefore: 6a + 4b = 320 ± 20 = 320 ± 6%
Questions: Try the questions below: Show all work
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1. X =a - 2b |
a =50.0 ± 1.0 |
b =24.0 ± 0.5 |
Ans: 2 ± 2
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2. X =a3 |
a =10.0 ± 0.3 |
b =0 |
Ans: 1000 ± 90 |
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3. |
a=100.0 ± 4.0 |
b =50.0 ±2.0 |
Ans: 14.1 ± 0.8
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4. X =
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a=0.200 ± 0.004 |
b =0.100 ± 0.003 |
c = 0.050 ± 0.002 |
Ans: 0.040 ± 0.005 |
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5. Suppose :
If P = (101 ± 4)N/m2, a = (0.068 ± 0.002)m, l = (0.040 ± 0.001)m, and w = (0.060 ± 0.001)m determine F and its uncertainty limits.
(ans: 0.35N ± 0.07N)
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