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Homework answers / question archive / When two competing teams are equally matched, the probability that each team wins any game is 0
When two competing teams are equally matched, the probability that each team wins any game is 0.5. The (NBA) championship goes to the team that wins four National Basketball Association games
in a best-of-seven series. If the teams were evenly matched, the probability that the final series ends
with one of the teams sweeping four straight games would be 2(0.5)4 =0.125 [team A wins in 4 games
with probability of (0.5)4
; team B can also win in 4 games with the same probability, so the probability
the series ends in 4 games is 2(0.5)4
].
Similarly team A can win in 5 games if team A wins 3 of the first 4 games and then wins game 5. So
team A wins in 5 games with probability 4C3(0.5)3
(0.5)*(0.5)=0.125 . But team B can also win in 5 games
with the same probability, so the probability that the series ends in 5 games is 0.25. Similar probability
calculations show that the probability is 0.3125 that the series lasts six games, and the probability is
0.3125 that the series lasts the full seven games. The table below shows the number of games it took
to decide each of the last 57 NBA champs.
Length of series 4 games 5 games 6 games 7 games
NBA finals 7 13 22 15
Do you think the teams are usually equally matched? Give statistical evidence to support your
conclusion. [30]