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Homework answers / question archive / A floor polisher has a rotating disk with a radius of 15 cm
A floor polisher has a rotating disk with a radius of 15 cm. The disk rotates at a constant angular velocity of 1.4 rev/s and is covered with a soft material that does the polishing. An operator holds the polisher in one place for 45s in order to buff an especially scuffed area of the floor. How far (in meters) does a spot on the outer edge of the disk move during this time?
The angle through during the time = 1.4 * 45 =63 (rev)
S = r * angle = 15 * (63 * 2 * 3.14 )=5934.6 (cm) = 59.35 (m)
