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Homework answers / question archive / An artist entered two paintings (Lighthouse and Old Cathedral) in a show

An artist entered two paintings (Lighthouse and Old Cathedral) in a show

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An artist entered two paintings (Lighthouse and Old Cathedral) in a show. He feels that the probabilities are 0.15, 0.18, and 0.11, respectively, that he will sell the Lighthouse, the Old Cathedral, or both. What is the probability that he will sell either of the two paintings?

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 the event that he will sell the Lighthouse
B: the event that he will sell the Old Cathedral

So, P(A)=0.15, P(B)=0.18 and P(AB)=0.11.

Now we want to compute P( A or B)

By a formula, P( A or B)=P(A)+P(B)-P(AB), we have

P( A or B)=P(A)+P(B)-P(AB)
=0.15+0.18-0.11=0.22

So, the probability that he will sell either of the two paintings is 0.22

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