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A parachutist of mass m falls vertically to the ground from a plane

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A parachutist of mass m falls vertically to the ground from a plane. Air resistance is mkv2 newtons, where v is his speed and g is the acceleration due to gravity. Take downwards as the positive direction, and the point where he falls from the plane as the origin O. (i) If x is the parachutist's displacement from O, deduce that di = (v2) = 2g – 2kv2 a = g – kv2 Since acceleration is the derivative of velocity, such that: d (v2) = g – kv2 dx