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The nucleus 6C12 consists of six protons and six neutrons held in close association by strong nuclear forces

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The nucleus 6C12 consists of six protons and six neutrons held in close association by strong nuclear forces. The atomic rest masses are

6C12: 12.000000u
1H1: 1.007825u
n: 1.008665u

in terms of the atomic mass unit u = 1.66 x 10^-27 kg. How much energy would be required to separate a 6C12 nucleus into its constituent protons and neutrons?

This problem has me totally confused. Am I using the formula for Relativistic kinetic energy:

K = (mc2/√1 - v2/c2) - mc2

or for rest energy:

E0 = mc2

or neither? How do I do this problem?