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Homework answers / question archive / The nucleus 6C12 consists of six protons and six neutrons held in close association by strong nuclear forces

The nucleus 6C12 consists of six protons and six neutrons held in close association by strong nuclear forces

Physics

The nucleus 6C12 consists of six protons and six neutrons held in close association by strong nuclear forces. The atomic rest masses are

6C12: 12.000000u
1H1: 1.007825u
n: 1.008665u

in terms of the atomic mass unit u = 1.66 x 10^-27 kg. How much energy would be required to separate a 6C12 nucleus into its constituent protons and neutrons?

This problem has me totally confused. Am I using the formula for Relativistic kinetic energy:

K = (mc2/√1 - v2/c2) - mc2

or for rest energy:

E0 = mc2

or neither? How do I do this problem?

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