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A light ray in air is incident on a water surface at an angle of 33

Physics

A light ray in air is incident on a water surface at an angle of 33.1 ? with respect to the normal to the surface. (Refraction index for water is 1.333) What is the angle of the refracted ray relative to this normal? Answer in units of ? .

 

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Use Shell's law

n1sin?θ?1 = n1sin?θ?2

1 × sin(33.1°) = 1.333 × sin?θ?2

?θ?2 = 24.2°

the angle of the refracted ray relative to this normal is 24.2°