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A light ray in air is incident on a water surface at an angle of 33
A light ray in air is incident on a water surface at an angle of 33.1 ? with respect to the normal to the surface. (Refraction index for water is 1.333) What is the angle of the refracted ray relative to this normal? Answer in units of ? .
Expert Solution
Use Shell's law
n1sin?θ?1 = n1sin?θ?2
1 × sin(33.1°) = 1.333 × sin?θ?2
?θ?2 = 24.2°
the angle of the refracted ray relative to this normal is 24.2°
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