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Lead thiocyanate, Pb(SCN)2, has a Ksp value of 2
Lead thiocyanate, Pb(SCN)2, has a Ksp value of 2.00×10−5.
1) Calculate the molar solubility of lead thiocyanate in 1.00 M KSCN.
Expert Solution
Given that Pb(SCN)2, has a Ksp value of 2.00×10−5
Pb(SCN)2 <-------------> Pb2+ + 2SCN-
s 2s s = molar solubility of lead thiocyanate
Ksp = [Pb2+] [SCN-]2
Given that [KSCN] = [SCN-] = 1 M
Hence,
Ksp = [s] [2s + 1 M ]2
2.00 × 10−5 = 4s3 + 4s2 + s
Since s is very small,
s3 and s2 can be neglected.
Then,
2.00×10−5 = s
s = 2.00×10−5 M
Therefore,
molar solubility of lead thiocyanate in 1.00 M KSCN = 2.00×10−5 M
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