Trusted by Students Everywhere
Why Choose Us?
0% AI Guarantee

Human-written only.

24/7 Support

Anytime, anywhere.

Plagiarism Free

100% Original.

Expert Tutors

Masters & PhDs.

100% Confidential

Your privacy matters.

On-Time Delivery

Never miss a deadline.

Myotonic dystrophy is an autosomal recessive disorder affecting 1 in 500 people in Quebec

Sociology May 14, 2021

Myotonic dystrophy is an autosomal recessive disorder affecting 1 in 500 people in Quebec.

a. What is the expected frequency for the dominant allele in the Quebec population?

b.What is the expected frequency for the recessive allele in the Quebec population?

c.What percent of the Quebec population would you expect to be homozygous for the normal (non-disease) allele?

d. Myotonic dystrophy affects one in 7500 people in all of Canada. What would be the expected frequency of carriers of myotonic dystrophy in Canada?

e.Assuming the population of Canada is 30 million people, what number of people in Canada would you expect to be carriers?

 

Expert Solution

Answer:

(a) 0.9552

(b) 0.04472

(c) 99.99%

(d) 2.283 %

(e) 684820 people

Step-by-step explanation

Lets apply Hardy-Weinberg equations;

p2 + 2pq + q2 = 1

p + q = 1

Whereby;

p = frequency of the dominant allele

q = frequency of the recessive allele

p2 = % of homozygous dominant individual in the population

2pq = % of heterozygous individual in the population

q2 = % of homozygous recessive individual

 

(a)

% of homozygous recessive individual = 1/500 x 100 = 0.2 % or 0.002 hence;

q2 = 0.002

q = (0.002)^1/2 =0.04472

p + q = 1

p = 1 - q

p = 1 - 0.04472 =0.9552

The frequency of the homozygous dominant allele = 0.9552

(c)

frequency of homozygous recessive allele = q =0.04472

(d)

% of homozygous normal for the allele = p2

p =0.9552

p2 = (0.9552)^2 = 0.9999 or

p2 = 0.9999 x 100% = 99.99%

(d)

q2 = 1/7500 x 100 = 0.013333 % or 0.00013333

q = (q2)^1/2

q = (0.000133333)^1/2 = 0.011547

p + q = 1

p = 1 - q

p = 1 - 0.011547

p = 0.98845

% of heterozygous individuals/carriers = 2pq

2pq = 2(0.98845 x 0.011547) = 0.022827

2pq = 0.022827 x 100 % = 2.283 %

(e)

Number of expected to carriers = percentage of carriers/100 x 30 million

Number of expected to carriers = 2.283/100 x 30000000

Number of people expected to be carries = 684820 people

Archived Solution
Unlocked Solution

You have full access to this solution. To save a copy with all formatting and attachments, use the button below.

Already a member? Sign In
Important Note: This solution is from our archive and has been purchased by others. Submitting it as-is may trigger plagiarism detection. Use it for reference only.

For ready-to-submit work, please order a fresh solution below.

Or get 100% fresh solution
Get Custom Quote
Secure Payment