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A uniform thin rod of mass m = 3

Mechanical Engineering Jan 14, 2021

A uniform thin rod of mass m = 3.7 kg and length L = 12 m can rotate about an axle through its center. Four forces are acting on it as shown in the figure. Their magnitudes are F_1 = 45 N, F_2 = 45 N, F_3 = 12 N and F_4 = 18 N. F_2 acts a distance d = 026 m from the center of mass. Calculate the magnitude Tau_1 of the torque due to force F_1, in newton meters. Calculate the magnitude Tau_2 of the torque due to force F_2 in newton meters. Calculate the magnitude Tau_3 of the torque due to force F_3 in newton meters. Calculate the magnitude Tau_4 of the torque due to force F_4 in newton meters. Calculate the angular acceleration alpha of the thin rod about its center of mass in radians per square second. Let the counter clockwise direction be positive. alpha

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