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If C(x) is the cost of producing x units of a commodity, then the average cost per unit is c(x) = C(x)/x
If C(x) is the cost of producing x units of a commodity, then the average cost per unit is c(x) = C(x)/x. Consider the cost function C(x) given below:
C(x) = 54,000 + 140x + 4x3/2
(a) Find the production level that will minimize the average cost. (Round your answer to the nearest whole number.)
(b) What is the minimum average cost? (Round your answer to the nearest dollar.)
Expert Solution
First, we calculate the average cost function:
C(x)=54000+140x+4x32c(x)=C(x)xc(x)=54000+140x+4x32xc(x)=54000x+140+4x12C(x)=54000+140x+4x32c(x)=C(x)xc(x)=54000+140x+4x32xc(x)=54000x+140+4x12
(a) Calculating the derivative and equaling it to zero, we determine the critical points:
c(x)=54000x+140+4x12c′(x)=−54000x2+412x−12c′(x)=−54000x2+2x−12=0−54000x2+2x−12=0−54000x2=−2x−1227000=x32x=(27000)23=900c(x)=54000x+140+4x12c′(x)=−54000x2+412x−12c′(x)=−54000x2+2x−12=0−54000x2+2x−12=0−54000x2=−2x−1227000=x32x=(27000)23=900
With the second derivative test, we verify that it is a minimum:
c′(x)=−54000x2+2x−12=−54000x−2+2x−12c′′(x)=108000x−3−x−32c′′(900)>0c′(x)=−54000x2+2x−12=−54000x−2+2x−12c″(x)=108000x−3−x−32c″(900)>0
(b) Evaluating in the function, we obtain the minimum average cost:
c(900)=54000900+140+4(900)12=60+140+120=320
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