I have a C programming question for you, where I will be required to modify a C program that counts the characters of a ASCII text file

I have a C programming question for you, where I will be required to modify a C program that counts the characters of a

ASCII text file.

This is the code, which is provided.

#include <stdbool.h>
#include <stdio.h>
typedef unsigned char BYTE;
int main(int argc, char *argv[])
{
    if (argc != 2)
    {
        printf("Usage: ./count INPUTn");
        return 1;
    }
    FILE *file = fopen(argv[1], "r");
    if (!file)
    {
        printf("Could not open file.n");
        return 1;
    }
    int count = 0;
    while (true)
    {
        BYTE b;
        fread(&b, 1, 1, file);
        if (feof(file))
        {
            break;
        }
        count++;
    }
    printf("Number of characters: %in", count);
}

The question is asking to modify this code, where instead of counting the ASCII characters, we have to make

a program that counts UTF-8 characters in a file.

Here is the questions:

The program above counts the number of characters in a file, assuming the file is encoded as ASCII. Modify the program so that it counts the number of characters in a file encoded as UTF-8.