EEEE1043 Coursework

Task:

For an isotropic point source located in the specific position as indicated in Fig. 1, develop a   general program that calculates the electromagnetic field from point p to point q. Assume the operation frequency is at 2.4 GHz. Plot the electric field vs distance (from point p to point q). You will need to use the reflection coefficient equation to calculate the reflected rays.  

Fig. 1. Geometry of the corridor.

Mathematically, the electric field of direct ray is written as follows:

1 ? j?r ? ??

Ei ? e ? ?      r ?4??

where r is the distance along the direct ray path, λ is the wavelength, ? is the wave

2^{? ? j?r  ?} number (also denoted as k is some literature,?_?    ), e is the phase factor, and    is

                                                                                                      ?                  4?

a parameter related to the antenna effect.

Submit your code and graphs (up to three figures) in one single document, see sample below:-

Sample solution 

% Sample Program  clear all;

f = 2.4*10^9;   % frequency (given) c = 3*10^8;     % speed of light beta = 2*pi*f/c;                % wave number

% to solve for the direct ray

tx = 0; ty = 4; tz = 2;         % tx [x,y,z] location rx = 10; ry = 3; rz = 2;        % rx [x,y,z] location rxv = rx:.01:22;                  % from p to q d = sqrt(((rxv-tx).^2)+((ry-ty)^2)+((rz-tz)^2)); % distance  Ed = (1./d).*exp(-j*beta*d);    % direct ray (line of sight) Edf = 20*log10(abs(Ed));        % direct ray alone plot(rxv,Edf) xlabel('Line Segment "pq"/m'),ylabel('E-field/dB')

Below is the marking scheme: -