Why Choose Us?
0% AI Guarantee
Human-written only.
24/7 Support
Anytime, anywhere.
Plagiarism Free
100% Original.
Expert Tutors
Masters & PhDs.
100% Confidential
Your privacy matters.
On-Time Delivery
Never miss a deadline.
Speedy Oil provides a single-server automobile oil change and lubrication service
Speedy Oil provides a single-server automobile oil change and lubrication service. Customers provide an arrival rate of 2.5 cars per hour. The service rate is 5 cars per hour. Assume that arrivals follow a Poisson probability distribution and that service times follow an exponential probability distribution.
b. What is the average time that a car waits for the oil and lubrication service to begin?
Expert Solution
b). Computation of the average time that a car waits for the oil and lubrication service to begin:-
Average number of cars in waiting line = (Arrival rate^2) / (Service rate * (Service rate - Arrival rate))
= (2.5^2) / (5*(5-2.5))
= 6.25 / 12.5
= 0.50
Average time = Average number of cars in waiting line / Arrival rate
= 0.50 / 2.5
= 0.20 hours Or 12 minutes
Archived Solution
You have full access to this solution. To save a copy with all formatting and attachments, use the button below.
For ready-to-submit work, please order a fresh solution below.





