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Assume that a company faces two mutually exclusive project options to invest
Assume that a company faces two mutually exclusive project options to invest. Initial costs and the cash flows along with the IRRs of each investment are given below for each option. Given that interest is 10%, find A and B. Project 1 (S) Project 2 (5) Year 0 1 2 3 - 17000 7450 4B 3*B 0,13 -23000 9920 5B ? 0,17 IRR Select one: a. A=22000, B-8000 b. A=26000, B = 4000 c. A=11600, B=2000 d. A10000, B-10000 0.A4300, B 6000 1. A-8000, B 9000
Expert Solution
Project-1
The initial investment during the initial time period or i is $17,000 and when i=1, 2, and 3 the cash flows or CFs are $7450, $4B, and $3B respectively. The IRR is 0.13 and the interest rate or r is 10% or 0.10. Therefore, based on the mathematical formula to calculate the IRR, IRR={CFs/(1+r)^i}-Initial investment
Therefore, based on the mathematical formula to calculate the IRR, it can be stated:-
IRR={CF1/(1+r)^1}+{CF2/(1+r)^2}+{CF3/(1+r)^3}-Initial investment
0.13={$7450/(1+0.10)^1}+{$4B/(1+0.10)^2}+{$3B/(1+0.10)^3}-$17,000
0.13=($7450/1.10)+($4B/1.21)+($3B/1.331)-$17,000
0.13=$6772.72+$4B/1.21+$3B/1.331-$17,000
0.13=$4B/1.21+$3B/1.331-$10,227.28
0.13=($5.324B+$3.63B-$16471.136)/1.61051
0.13=($8.95B-$16471.136)/1.61051
0.21=$8.95B-$16471.136
$16471.136+0.21=$8.95B
$16471.346=$8.95B
$16471.346/$8.95=B
$1840.374 approximately=B
Hence, the value of B, in tis case is approximately $1840.374 which is closes to $2000s given in one of the answer choices or options in the question.
Project-2
The initial investment in time period i=0 is $23,000 and the CFs in time period i=1,2, and 3 are respectively $9920, $5B, and A. The interest rate or r is 10% or 0.10 and the IRR is 0.17. Now, plugging the value of B obtained from the IRR calculation of project-1 into the CF of i=2, we get=$5*($1840.374)=$9201.87.
Therefore, again using the mathematical formula to calculate the IRR, we can get:-
IRR={CF1/(1+r)^1}+{CF2/(1+r)^2}+{CF3/(1+r)^3}-Initial investment
0.17={$9920/(1+0.10)^1}+{$9201.87/(1+0.10)^2}+{$A/(1+0.10)^3}-$23,000
0.17=($9920/1.10)+($9201.87/1.21)+($A/1.331)-$23,000
0.17=$9018.18+$7604.85+$A/1.331-$23,000
0.17=$A/1.331-$6376.97
$6376.97+0.17=$A/1.331
$6377.14=$A/1.331
$10,487.97 approximately =$A
Thus, the value of $A is approximately $10,487.97 which is closest to $11,600, in this case. Therefore, the answer here would be option c. given in the answer choices or options or A=11600, b=2000 approximately.
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