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The diagram below shows the construction EY↔ through point P parallel to NF↔

Math Apr 18, 2021

The diagram below shows the construction EY through point P parallel to NF.

Which theorem justifies this method of construction?

A. If two lines in a plane are cut by a transversal to form congruent corresponding angles, then the lines are parallel.

B. If two lines in a plane are cut by a transversal to form congruent alternate exterior angles, then the lines are parallel.

C. If two lines in a plane are perpendicular to a transversal at different points, then the lines are parallel.

D. If two lines in a plane are cut by a transversal to form congruent alternative, interior angles, then the lines are parallel.

Use the figure to drag in the missing statement or reason to complete the proof.

Given: x || y and Ð6 @ Ð11.

Prove: i || m

   x                               y

     6                                  8                       l

9                                 11                           m

Statements

Reasons

1. X // y and Ð6 @ Ð11

1. Given

2. Ð6 @ Ð8

2. Corresponding Angles Postulate

3. Ð11 @ Ð8

3. Alternate Interior Angles Theorem

4. I // m

4. Converse of Reflexive Property of Equality

 

  • Ð11 @ Ð8
  • Ð6 @ Ð8
  • Alternate Interior Angles Theorem
  • Corresponding Angles Postulate
  • Reflexive Property of Equality
  • Transitive Property of Equality

1    x   2                                         3         4            l

       5 9       

106                                                                   711

812

      13       14                                       15       16         m

Tell which lines, if any are parallel based on each of the following facts. (Note: name the lines in alphabetical order!) Then state which theorem or post justifies your answer.

Ð4 @ Ð13 ?  || ?   by the ?

mÐ10 + mÐ11 = 180° makes ? || ?  by the ?

Ð9 @ Ð16 makes ? || ? by the ?

Ð7 @ Ð12 makes ? || ? by the ?

mÐ1 + mÐ3 = 180° makes ? || ? by the ?

Ð6 @ Ð14 makes ? || ? by the ?

Expert Solution

PFA

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