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The average score of a statistics class was 71 with a standard deviation of 10
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The average score of a statistics class was 71 with a standard deviation of 10.
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What is the z score of a student with a grade of 68? (2.5 pts)
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What is the z score of a student with a grade of 80? (2.5 pts)
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Using the same data in #1 answer the following:
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Approximately 68% (one standard deviation) of the scores are between ________ and _________ (2.5 pts)
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Approximately 95% (two standard deviation) of the scores are between _________ and _________ (2.5 pts)
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Most values of a standard normal distribution are between __________. (3 pts)
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-3 and 3
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0 and 1
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0 and 3
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1 and 3
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(a) If the standard deviation of a data set is 1.3, what is the variance? (2.5 pts)
(b) If the variance is 36, what is the standard deviation? (2.5 pts) -
Let X have a normal distribution with mean µ = 20 and standard deviation σ = 4.
Determine the area in the normal curve for which:-
P(X > 28) (2.5 pts)
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P(X < 12) (2.5 pts)
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P(16 < X < 24) (2.5 pts)
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The IQ scores of students listed below are from a SAMPLE of MATH 300 class.
IQ Scores
92
110
105
96
120
100
90
98
110
95
102
99
93
119
106
103
91
101
97
105
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What is the mean IQ score? Round to the nearest whole number. (2.5 pts)
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Compute the IQ scores within plus/minus one standard deviation? Two answers. Round to the nearest whole numbers. (2.5 pts)
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Compute the IQ scores within plus/minus two standard deviation? Two answers. (2.5 pts)
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Let X have a normal distribution with µ= 10 and standard deviation σ= 2. Transform X to the standard normal form Z and match the following probability statements:
a) P(X>14) 1) P(Z<-1)
b) P(X<8) 2) P(-2 < Z < 2)
c) P(6 < X < 14) 3) P(Z > 2)
a) is matched to ___________ (2.5 pts)
b) is matched to ___________ (2.5 pts)
c) is matched to ___________ (2.5 pts) -
Let X have a normal distribution with mean µ= 30 and standard deviation σ= 10. Calculate P(X>40). Round to two decimal places. (4 pts)
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For a standard normal variable Z, compute P(Z<1.5). Round your answer to two decimal places. (3 pts)
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A larger standard deviation of a normal distribution indicates that the distribution becomes (2.5 pts)
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narrower and more peaked
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flatter and wider
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more skewed to the right
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more skewed to the left
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